Solve dydx=xy\dfrac{dy}{dx} = xydxdy=xy with y(0)=2y(0) = 2y(0)=2. Then y(1)=y(1) =y(1)=A2e2\sqrt{e}2echeck_circleBe1/2e^{1/2}e1/2C2e2e2eD2e\sqrt{2e}2eExplanationSeparate: dy/y=x dx⇒ln∣y∣=x2/2+Cdy/y = x\,dx \Rightarrow \ln|y| = x^2/2 + Cdy/y=xdx⇒ln∣y∣=x2/2+C. y(0)=2y(0)=2y(0)=2: ln2=C\ln 2 = Cln2=C. So y=2ex2/2y = 2 e^{x^2/2}y=2ex2/2. y(1)=2e1/2=2ey(1) = 2e^{1/2} = 2\sqrt{e}y(1)=2e1/2=2e.