Extrema: First Derivative Test

AP Calculus AB· difficulty 2/5

x x=2

On the interval shown, f(x)<0f'(x) < 0 on:

  • A

    (2,4)(2, 4)

  • B

    Everywhere

  • C

    (0,2)(0, 2)

    check_circle
  • D

    Nowhere

Explanation

ff decreases from x=0x=0 to x=2x=2 (the minimum), so f<0f'<0 on (0,2)(0,2).

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