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Defining Average and Instantaneous Rates of Change

AP Calculus AB· difficulty 2/5

x (1,3) (5,9)

The secant slope between (1,3)(1,3) and (5,9)(5,9) on the graph of ff equals:

  • A

    32\tfrac{3}{2}

    check_circle
  • B

    66

  • C

    23\tfrac{2}{3}

  • D

    44

Explanation

Slope =9−35−1=64=32= \frac{9-3}{5-1} = \frac{6}{4} = \frac{3}{2}.

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