limh→0cos(0+h)−cos0h\displaystyle\lim_{h\to 0}\dfrac{\cos(0+h) - \cos 0}{h}h→0limhcos(0+h)−cos0 equalsA−1-1−1B000check_circleCDoes not existD111ExplanationThis is f′(0)f'(0)f′(0) for f(x)=cosxf(x) = \cos xf(x)=cosx. f′(x)=−sinxf'(x) = -\sin xf′(x)=−sinx; −sin(0)=0-\sin(0) = 0−sin(0)=0.