Use the quotient rule on tanx=sinx/cosx\tan x = \sin x/\cos xtanx=sinx/cosx: ddxtanx=\dfrac{d}{dx}\tan x =dxdtanx=ABoth B and Ccheck_circleBsecx\sec xsecxC1+tan2x1 + \tan^2 x1+tan2xDsec2x\sec^2 xsec2xExplanation(cosx⋅cosx−sinx⋅(−sinx))/cos2x=1/cos2x=sec2x=1+tan2x(\cos x \cdot \cos x - \sin x \cdot (-\sin x))/\cos^2 x = 1/\cos^2 x = \sec^2 x = 1 + \tan^2 x(cosx⋅cosx−sinx⋅(−sinx))/cos2x=1/cos2x=sec2x=1+tan2x.