If f(x)=x3−4x+7f(x) = x^3 - 4x + 7f(x)=x3−4x+7, then f′(2)=f'(2) =f′(2)=A121212B888check_circleC−4-4−4D000Explanationf′(x)=3x2−4f'(x) = 3x^2 - 4f′(x)=3x2−4. f′(2)=12−4=8f'(2) = 12 - 4 = 8f′(2)=12−4=8.