For 2x+3y=62x + 3y = 62x+3y=6, dy/dx=dy/dx =dy/dx=A−2/3-2/3−2/3check_circleB−3/2-3/2−3/2C3/23/23/2D2/32/32/3ExplanationDifferentiate: 2+3y′=0⇒y′=−2/32 + 3 y' = 0 \Rightarrow y' = -2/32+3y′=0⇒y′=−2/3.