ddxx2+13=\dfrac{d}{dx}\sqrt[3]{x^2 + 1} =dxd3x2+1=A13(x2+1)−2/3\dfrac{1}{3}(x^2+1)^{-2/3}31(x2+1)−2/3B2x3x2+13\dfrac{2x}{3\sqrt[3]{x^2+1}}33x2+12xC2x3(x2+1)−2/3\dfrac{2x}{3}(x^2+1)^{-2/3}32x(x2+1)−2/3check_circleD2x3(x2+1)1/3\dfrac{2x}{3}(x^2+1)^{1/3}32x(x2+1)1/3Explanation(x2+1)1/3(x^2+1)^{1/3}(x2+1)1/3 → 13(x2+1)−2/3⋅2x=2x3(x2+1)2/3\tfrac{1}{3}(x^2+1)^{-2/3} \cdot 2x = \tfrac{2x}{3(x^2+1)^{2/3}}31(x2+1)−2/3⋅2x=3(x2+1)2/32x.