Use L(x)=1+x2L(x) = 1 + \tfrac{x}{2}L(x)=1+2x (linearization of 1+x\sqrt{1+x}1+x at x=0x = 0x=0) to estimate 1.04\sqrt{1.04}1.04.A1.081.081.08B1.021.021.02check_circleC1.201.201.20D1.041.041.04ExplanationL(0.04)=1+0.02=1.02L(0.04) = 1 + 0.02 = 1.02L(0.04)=1+0.02=1.02.