Area between y=sinxy = \sin xy=sinx and y=cosxy = \cos xy=cosx on [0,π/4][0, \pi/4][0,π/4] isA2−1\sqrt 2 - 12−1check_circleB2\sqrt 22C1−21 - \sqrt 21−2D111ExplanationOn this interval cosx≥sinx\cos x \ge \sin xcosx≥sinx. ∫0π/4(cosx−sinx) dx=[sinx+cosx]0π/4=2/2+2/2−0−1=2−1\int_0^{\pi/4}(\cos x - \sin x)\,dx = [\sin x + \cos x]_0^{\pi/4} = \sqrt 2/2 + \sqrt 2/2 - 0 - 1 = \sqrt 2 - 1∫0π/4(cosx−sinx)dx=[sinx+cosx]0π/4=2/2+2/2−0−1=2−1.