Mean Value Theorem and Extreme Value Theorem

AP Calculus AB· difficulty 3/5

Same f(x)=x312xf(x) = x^3 - 12x on [3,3][-3, 3]. Absolute <strong>minimum</strong> is

  • A

    16-16

    check_circle
  • B

    00

  • C

    1616

  • D

    9-9

Explanation

From the four candidate values, 16-16 at x=2x = 2 is least.

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