Tonicity and Osmoregulation

AP Biology· difficulty 4/5

Water potential (psi) = pressure potential + solute potential. For an open beaker at 25 C, pressure potential = 0, so psi = solute potential = -iCRT, where i is the ionization constant (1 for sucrose), C is molarity, R = 0.0831 (L bar)/(mol K), T = 298 K. The potato cylinders showed isotonic mass change at 0.2 M sucrose.

What is the calculated water potential of the potato cells?

  • A

    About 0 bars

  • B

    About -4.95 bars

    check_circle
  • C

    About -2.50 bars

  • D

    About -10.0 bars

Explanation

psi = -(1)(0.2)(0.0831)(298) = -4.95 bars. At isotonic equilibrium, the potato cell water potential matches the external 0.2 M solution.

Want 10 more like this — adaptive to your weak spots?

Related questions