Hardy-Weinberg Equilibrium

AP Biology· difficulty 2/5

A population of 100 individuals is genotyped at one locus. The table shows observed genotype frequencies.

Genotype Frequency Count AA 0.36 36 Aa 0.48 48 aa 0.16 16 N = 100

What is the frequency of the dominant allele A in this population?

  • A

    0.4

  • B

    0.6

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  • C

    0.36

  • D

    0.84

Explanation

p = freq(AA) + (1/2)freq(Aa) = 0.36 + 0.24 = 0.60. Therefore the A allele frequency is 0.6.

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