Rotational Equilibrium and Newton's First Law in Rotational Form

AP Physics 1· difficulty 3/5

A uniform horizontal sign of mass 5 kg5~\text{kg} and length 1.0 m1.0~\text{m} is suspended by two vertical ropes, one at each end. Each rope has tension equal to (using g10 m/s2g \approx 10~\text{m/s}^2):

  • A

    25 N25~\text{N} on left, 50 N50~\text{N} on right

  • B

    25 N25~\text{N}

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  • C

    50 N50~\text{N}

  • D

    50 N50~\text{N} on each rope

Explanation

By symmetry, each rope supports half the weight: T=mg/2=25 NT = m g/2 = 25~\text{N}.

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