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Torque

AP Physics 1· difficulty 2/5

A wheel of radius 0.50 m0.50~\text{m} has a 20 N20~\text{N} tangential force at the top (toward right) and a 10 N10~\text{N} tangential force at the bottom (also toward right). The net torque about the center is

  • A

    5 N⋅m5~\text{N·m}

    check_circle
  • B

    15 N⋅m15~\text{N·m}

  • C

    00

  • D

    10 N⋅m10~\text{N·m}

Explanation

Both forces produce CCW torques of magnitudes 20⋅0.5=1020 \cdot 0.5 = 10 and 10⋅0.5=510 \cdot 0.5 = 5, in the same sense? No — top-rightward goes CCW, bottom-rightward goes CW. Net =∣10−5∣=5 N⋅m= |10 - 5| = 5~\text{N·m}.

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