Rotational Equilibrium and Newton's First Law in Rotational Form

AP Physics 1· difficulty 2/5

40 kg m 1.5 m 2.0 m

A 40 kg40~\text{kg} child sits 1.5 m1.5~\text{m} to the left of a seesaw's fulcrum. To balance, what mass must be placed 2.0 m2.0~\text{m} to the right?

  • A

    30 kg30~\text{kg}

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  • B

    53 kg53~\text{kg}

  • C

    40 kg40~\text{kg}

  • D

    20 kg20~\text{kg}

Explanation

Balance: m1gd1=m2gd2m2=(40)(1.5)/2.0=30 kgm_1 g d_1 = m_2 g d_2 \Rightarrow m_2 = (40)(1.5)/2.0 = 30~\text{kg}.

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