A disk of moment of inertia I0 spins at \omega0. A lump of putty of mass m is dropped onto the rim at radius R and sticks. The disk's final angular velocity is

\dfrac{I0\,\omega0}{I0 + m R^2} Conservation of angular momentum: I0 \omega0 = (I0 + m R^2)\,\omega' \Rightarrow \omega' = I0 \omega0/(I0 + m R^2).

\dfrac{I0\,\omega0}{I0 - m R^2}

\dfrac{I0\,\omega0}{I0 + m R^2}

Conservation of Angular Momentum

AP Physics 1· difficulty 3/5

I_0

Explanation

I_0 \omega_0 = (I_0 + m R^2)\,\omega' \Rightarrow \omega' = I_0 \omega_0/(I_0 + m R^2)

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