A 0.40\text{kg} mass on a vertical spring stretches it 0.10\text{m} at equilibrium (using g \approx 10\text{m/s}^2). The period of small oscillations is

2\pi\sqrt{0.01}\text{s} k = m g/x = 4/0.1 = 40\text{N/m}. T = 2\pi\sqrt{m/k} = 2\pi\sqrt{0.40/40} = 2\pi\sqrt{0.01} = 2\pi(0.10) \approx 0.63\text{s}.

Frequency and Period of SHM

AP Physics 1· difficulty 2/5

0.40~\text{kg}

A
$\pi/\sqrt 5~\text{s}$
B
$2\pi\sqrt{0.01}~\text{s}$
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C
$2\pi/10~\text{s}$
D
$\pi/5~\text{s}$

Explanation

k = m g/x = 4/0.1 = 40~\text{N/m}

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