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Representing and Analyzing SHM

AP Physics 1· difficulty 3/5

A mass oscillates as x(t)=(0.15 m)cos⁡(4t)x(t) = (0.15~\text{m})\cos(4 t), with tt in seconds. What is the position at t=π/16 st = \pi/16~\text{s}?

  • A

    0.15 m0.15~\text{m}

  • B

    0.106 m0.106~\text{m}

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  • C

    −0.15 m-0.15~\text{m}

  • D

    00

Explanation

Argument: 4⋅π/16=π/44 \cdot \pi/16 = \pi/4. x=0.15cos⁡(π/4)=0.15⋅(2/2)≈0.106 mx = 0.15\cos(\pi/4) = 0.15 \cdot (\sqrt{2}/2) \approx 0.106~\text{m}.

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