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Representing and Analyzing SHM

AP Physics 1· difficulty 2/5

For the oscillator above (m=0.25 kgm = 0.25~\text{kg}, k=100 N/mk = 100~\text{N/m}, A=0.10 mA = 0.10~\text{m}), what is the maximum acceleration?

  • A

    40 m/s240~\text{m/s}^2

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  • B

    10 m/s210~\text{m/s}^2

  • C

    25 m/s225~\text{m/s}^2

  • D

    4.0 m/s24.0~\text{m/s}^2

Explanation

amax⁡a_{\max} occurs at extremes where force is greatest: amax⁡=kA/m=(100)(0.10)/0.25=40 m/s2a_{\max} = k A / m = (100)(0.10)/0.25 = 40~\text{m/s}^2.

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