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Potential Energy

AP Physics 1· difficulty 2/5

Stretching a spring 0.20 m0.20~\text{m} from natural length stores 4.0 J4.0~\text{J}. The spring constant is

  • A

    200 N/m200~\text{N/m}

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  • B

    100 N/m100~\text{N/m}

  • C

    50 N/m50~\text{N/m}

  • D

    400 N/m400~\text{N/m}

Explanation

U=12kx2⇒k=2U/x2=8/0.04=200 N/mU = \tfrac{1}{2}k x^2 \Rightarrow k = 2U/x^2 = 8/0.04 = 200~\text{N/m}.

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