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Potential Energy

AP Physics 1· difficulty 1/5

A spring with constant k=200 N/mk = 200~\text{N/m} is compressed 0.10 m0.10~\text{m}. How much elastic potential energy is stored?

  • A

    20 J20~\text{J}

  • B

    2.0 J2.0~\text{J}

  • C

    0.5 J0.5~\text{J}

  • D

    1.0 J1.0~\text{J}

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Explanation

Us=12kx2=12(200)(0.10)2=1.0 JU_s = \tfrac{1}{2} k x^2 = \tfrac{1}{2}(200)(0.10)^2 = 1.0~\text{J}.

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