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Conservation of Linear Momentum

AP Physics 1· difficulty 3/5

A 0.020 kg0.020~\text{kg} bullet moving at 400 m/s400~\text{m/s} passes through a 2.0 kg2.0~\text{kg} block on a frictionless surface. After passing, the bullet has speed 200 m/s200~\text{m/s} (same direction). The block's speed afterward is

  • A

    4.0 m/s4.0~\text{m/s}

  • B

    10 m/s10~\text{m/s}

  • C

    2.0 m/s2.0~\text{m/s}

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  • D

    1.0 m/s1.0~\text{m/s}

Explanation

0.020(400)=0.020(200)+2.0 v⇒8−4=2v⇒v=2.0 m/s0.020(400) = 0.020(200) + 2.0\,v \Rightarrow 8 - 4 = 2 v \Rightarrow v = 2.0~\text{m/s}.

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