Change in Momentum and Impulse

AP Physics 1· difficulty 2/5

A 1500 kg1500~\text{kg} car at 20 m/s20~\text{m/s} decelerates to a stop in 4.0 s4.0~\text{s}. The average net force is

  • A

    5000 N5000~\text{N}

  • B

    3000 N3000~\text{N}

  • C

    30,000 N30{,}000~\text{N}

  • D

    7500 N7500~\text{N}

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Explanation

F=Δp/Δt=1500(20)/4=7500 NF = \Delta p/\Delta t = 1500(20)/4 = 7500~\text{N}.

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