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Displacement, Velocity, and Acceleration

AP Physics 1· difficulty 2/5

A ball is thrown up at 10 m/s10~\text{m/s} from ground. Using g≈10 m/s2g \approx 10~\text{m/s}^2, what is its height at t=1.5 st = 1.5~\text{s}?

  • A

    3.75 m3.75~\text{m}

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  • B

    15 m15~\text{m}

  • C

    1.25 m1.25~\text{m}

  • D

    11.25 m11.25~\text{m}

Explanation

y=v0t−12gt2=10(1.5)−5(2.25)=15−11.25=3.75 my = v_0 t - \tfrac{1}{2}g t^2 = 10(1.5) - 5(2.25) = 15 - 11.25 = 3.75~\text{m}.

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