A ball passes a window of height h = 1.5\text{m} in 0.10\text{s} on its way down. Using g \approx 10\text{m/s}^2, what is the ball's speed at the <strongtop</strong of the window?

14.5\text{m/s} Average speed crossing window = 1.5/0.10 = 15\text{m/s}. Speed at top v, at bottom v + g(0.10) = v + 1. Average = v + 0.5 = 15 \Rightarrow v = 14.5\text{m/s}.

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Acemy

Displacement, Velocity, and Acceleration

AP Physics 1· difficulty 3/5

h = 1.5~\text{m}

A
$5~\text{m/s}$
B
$0.5~\text{m/s}$
C
$20~\text{m/s}$
D
$14.5~\text{m/s}$
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Explanation

= 1.5/0.10 = 15~\text{m/s}

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