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Displacement, Velocity, and Acceleration

AP Physics 1· difficulty 1/5

A ball thrown straight up reaches maximum height in 2.5 s2.5~\text{s}. Using g≈10 m/s2g \approx 10~\text{m/s}^2, what was its initial speed?

  • A

    5 m/s5~\text{m/s}

  • B

    20 m/s20~\text{m/s}

  • C

    25 m/s25~\text{m/s}

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  • D

    12.5 m/s12.5~\text{m/s}

Explanation

At the peak, v=0v = 0. Using v=v0−gtv = v_0 - g t: v0=gt=(10)(2.5)=25 m/sv_0 = g t = (10)(2.5) = 25~\text{m/s}.

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