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Displacement, Velocity, and Acceleration

AP Physics 1· difficulty 2/5

A ball is thrown straight up from the ground with initial speed 15 m/s15~\text{m/s}. Using g≈10 m/s2g \approx 10~\text{m/s}^2, how high does it rise?

  • A

    11 m11~\text{m}

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  • B

    15 m15~\text{m}

  • C

    22 m22~\text{m}

  • D

    7.5 m7.5~\text{m}

Explanation

At the peak v=0v = 0, so 0=v02−2gh0 = v_0^2 - 2g h gives h=v02/(2g)=225/20=11.25≈11 mh = v_0^2/(2g) = 225/20 = 11.25 \approx 11~\text{m}.

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