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Fluids and Conservation Laws (Continuity, Bernoulli)

AP Physics 1· difficulty 4/5

Water flows horizontally through a pipe. At point 1, v1=2v_1 = 2 m/s and at point 2 (narrower), v2=6v_2 = 6 m/s. With ρ=1000\rho = 1000 kg/m3^3, what is P1−P2P_1 - P_2?

  • A

    8.0×1038.0\times10^3 Pa

  • B

    2.0×1042.0\times10^4 Pa

  • C

    1.6×1041.6\times10^4 Pa

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  • D

    4.0×1044.0\times10^4 Pa

Explanation

Bernoulli: P1−P2=12ρ(v22−v12)=500(36−4)=1.6×104P_1 - P_2 = \tfrac12 \rho (v_2^2 - v_1^2) = 500(36-4) = 1.6\times10^4 Pa.

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