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Fluids and Conservation Laws (Continuity, Bernoulli)

AP Physics 1· difficulty 4/5

v1, A1 v2, A2

Water flows through a pipe at v1=4.0v_1 = 4.0 m/s in a section of area A1=0.06A_1 = 0.06 m2^2. The pipe narrows to A2=0.02A_2 = 0.02 m2^2. What is the speed v2v_2?

  • A

    44 m/s

  • B

    1.31.3 m/s

  • C

    88 m/s

  • D

    1212 m/s

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Explanation

A1v1=A2v2A_1 v_1 = A_2 v_2, so v2=(0.06/0.02)(4.0)=12v_2 = (0.06/0.02)(4.0) = 12 m/s.

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