Reference Frames and Relative Motion

AP Physics 1· difficulty 4/5

far bank near bank v_b v_r

A river of width WW flows with speed vrv_r. A boat moves at speed vbv_b relative to water. To minimize the time to reach the far bank, the boat must aim straight across (perpendicular to the banks). What is the minimum crossing time and how far downstream does the boat land?

  • A

    time W/(vb+vr)W/(v_b + v_r), drift Wvr/(vb+vr)W v_r/(v_b+v_r)

  • B

    time W/vbW/v_b, drift Wvr/vbW v_r / v_b

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  • C

    time W/(vbvr)W/(v_b - v_r), drift WW

  • D

    time W/vb2vr2W/\sqrt{v_b^2 - v_r^2}, drift 00

Explanation

Aiming perpendicular gives the largest cross-stream component vbv_b, so the time is W/vbW/v_b. During that time the current carries the boat a distance vr(W/vb)=Wvr/vbv_r \cdot (W/v_b) = W v_r/v_b downstream.

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