AP Physics 1· difficulty 4/5
A 2 kg puck moving east at 4 m/s collides with a stationary 2 kg puck. After collision the first puck moves at 3 m/s at 30° north of east. The second puck's velocity has magnitude
m/s
m/s
m/s
m/s
Explanation
Conserve momentum: p_x: 8 = 2·3·cos30° + 2v_x → v_x ≈ (8-5.196)/2 = 1.40 p_y: 0 = 2·3·sin30° + 2v_y → v_y = -1.5 |v| = √(1.40² + 1.5²) ≈ 2.05 m/s.
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