A 1500 kg car going 20 m/s skids to rest over 50 m. The average friction force is approximately
- Acheck_circle
N
- B
N
- C
N
- D
N
Explanation
KE = (1/2)(1500)(400) = 300000 J. Work = F·d → F = 300000/50 = 6000 N.
Work and Mechanical Energy
AP Physics 1· difficulty 4/5
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