Kinetic and Static Friction

AP Physics 1· difficulty 4/5

A 2.0 kg block sits on a horizontal surface with μs=0.40\mu_s = 0.40. The maximum horizontal force that can be applied without the block sliding is (g=10g = 10 m/s²)

  • A

    0.40 N

  • B

    8.0 N (μsmg\mu_s mg)

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  • C

    20 N

  • D

    2.0 N

Explanation

Max static friction = μsN=μsmg=0.40(2.0)(10)=8.0\mu_s N = \mu_s mg = 0.40(2.0)(10) = 8.0 N.

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