A solid object of density 0.60 \times 10^3 kg/m³ floats in water (density 1.0 \times 10^3 kg/m³). The fraction of the object's volume submerged is

60% (Archimedes: \rho{obj}/\rho{fluid}) Floating equilibrium: weight = buoyant force. \rho{obj} V g = \rhow V{sub} g. So V{sub}/V = \rho{obj}/\rhow = 0.60 = 60%.

60% (Archimedes: \rho{obj}/\rho{fluid})

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Acemy

Fluids and Newton's Laws (Buoyancy)

AP Physics 1· difficulty 4/5

0.60 \times 10^3

A
$\rho_{obj}/\rho_{fluid}$
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B
$100%$
C
$40%$
D
$60%$

Explanation

\rho_{obj} V g = \rho_w V_{sub} g

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