A block of mass 5.0 kg slides down a 30° incline with kinetic friction coefficient \muk = 0.20. The acceleration is closest to (g = 10 m/s²)

3.3 m/s² (a = g(\sin\theta - \muk\cos\theta)) a = g(\sin 30° - 0.20 \cos 30°) = 10(0.500 - 0.173) = 3.27 m/s².

3.3 m/s² (a = g(\sin\theta - \muk\cos\theta))

Kinetic and Static Friction

AP Physics 1· difficulty 4/5

5.0

Explanation

a = g(\sin 30° - 0.20 \cos 30°) = 10(0.500 - 0.173) = 3.27

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