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Newton's Second Law (Translational Dynamics)

AP Physics 1· difficulty 3/5

The same car has tires with μs=0.50\mu_s = 0.50. What is the maximum speed it can take the curve without skidding? (g≈10 m/s2g \approx 10~\text{m/s}^2.)

  • A

    20 m/s20~\text{m/s}

  • B

    25 m/s25~\text{m/s}

  • C

    10 m/s10~\text{m/s}

  • D

    14 m/s14~\text{m/s}

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Explanation

μsmg=mv2/r⇒vmax=μsgr=(0.50)(10)(40)=200≈14 m/s\mu_s m g = m v^2/r \Rightarrow v_\text{max} = \sqrt{\mu_s g r} = \sqrt{(0.50)(10)(40)} = \sqrt{200} \approx 14~\text{m/s}.

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