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Fluids and Newton's Laws (Buoyancy)

AP Physics 1· difficulty 3/5

For the same block (W = 20 N in air, V=5×10−4 m3V = 5 \times 10^{-4}~\text{m}^3), its density is

  • A

    3000 kg/m33000~\text{kg/m}^3

  • B

    1000 kg/m31000~\text{kg/m}^3

  • C

    4000 kg/m34000~\text{kg/m}^3

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  • D

    2000 kg/m32000~\text{kg/m}^3

Explanation

m=W/g=2.0 kgm = W/g = 2.0~\text{kg}. ρ=m/V=2.0/(5×10−4)=4000 kg/m3\rho = m/V = 2.0/(5 \times 10^{-4}) = 4000~\text{kg/m}^3.

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