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Internal Structure and Density

AP Physics 1· difficulty 3/5

A solid block weighs 20 N20~\text{N} in air and 15 N15~\text{N} when fully submerged in water. Its volume (using ρw=1000 kg/m3\rho_w = 1000~\text{kg/m}^3, g≈10 m/s2g \approx 10~\text{m/s}^2) is

  • A

    10−3 m310^{-3}~\text{m}^3

  • B

    2×10−3 m32 \times 10^{-3}~\text{m}^3

  • C

    1.5×10−3 m31.5 \times 10^{-3}~\text{m}^3

  • D

    5×10−4 m35 \times 10^{-4}~\text{m}^3

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Explanation

Buoyancy: FB=20−15=5 NF_B = 20 - 15 = 5~\text{N}. V=FB/(ρg)=5/10000=5×10−4 m3V = F_B/(\rho g) = 5/10000 = 5 \times 10^{-4}~\text{m}^3.

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