Fluids and Newton's Laws (Buoyancy)

AP Physics 1· difficulty 3/5

Ice has density ρi=920 kg/m3\rho_i = 920~\text{kg/m}^3; sea water has ρw=1025 kg/m3\rho_w = 1025~\text{kg/m}^3. What fraction of an iceberg's volume is <strong>above</strong> water?

  • A

    About 90%90\%

  • B

    About 2%2\%

  • C

    About 50%50\%

  • D

    About 10%10\%

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Explanation

Floating: Vsub/V=ρi/ρw=920/10250.90V_{\text{sub}}/V = \rho_i/\rho_w = 920/1025 \approx 0.90. Above water: 10.900.101 - 0.90 \approx 0.10, so about 10%10\%.

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