Answer: 17 The enhanced for-loop visits every element. 5+3+8+1 = 17.

<codefor (int x : arr) sum += x;</code is equivalent to

Answer: Index-based for loop summing all elements Enhanced-for iterates each element in order.

Answer: 1 2 3 The for-each loop variable x is a copy of each element. Reassigning x does not modify the underlying array. To modify, you must use a standard for-loop with an index.

AP Computer Science A · Topic 6.3

Enhanced for Loop for Arrays Practice

Q: <codefor (int x : arr) sum += x;</code is equivalent to

Answer: Index-based for loop summing all elements Enhanced-for iterates each element in order.

Q: What is printed?

Answer: 1 2 3 The for-each loop variable x is a copy of each element. Reassigning x does not modify the underlying array. To modify, you must use a standard for-loop with an index.

Part of Array.

Practice questions

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Sample questions

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Sample 1difficulty 2/5
```
int[] a = {5, 3, 8, 1};
int total = 0;
for (int x : a) {
  total += x;
}
System.out.println(total);
```
$What is printed?$
- A
  $17$
  check_circle
- B
  $16$
- C
  $15$
- D
  $1$
Why
$The enhanced for-loop visits every element. 5+3+8+1 = 17.$
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Sample 2difficulty 3/5
$<code> for (int x : arr) sum += x; </code> is equivalent to$
- A
  $Sum first element only$
- B
  $Index-based for loop summing all elements$
  check_circle
- C
  $Sum elements at even indices$
- D
  $Compile error$
Why
$Enhanced-for iterates each element in order.$
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Sample 3difficulty 3/5
```
int[] a = {1, 2, 3};
for (int x : a) {
  x = x * 2;
}
System.out.println(a[0] + " " + a[1] + " " + a[2]);
```
$What is printed?$
- A
  $1 2 3$
  check_circle
- B
  $2 4 6$
- C
  $0 0 0$
- D
  $Compilation error$
Why
$The for-each loop variable x is a copy of each element. Reassigning x does not modify the underlying array. To modify, you must use a standard for-loop with an index.$
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Sample 4difficulty 4/5
$Inside <code> for (int x : arr) x = 0; </code>$
- A
  $Sets all array elements to 0$
- B
  $Throws exception$
- C
  $Compile error$
- D
  $Sets local copy x to 0; array unchanged$
  check_circle
Why
$<code> x </code> is a local copy of each element (for primitives); modification doesn't affect array.$
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Sample 5difficulty 4/5
$The enhanced for loop <code> for (int x : arr) { ... } </code>$
- A
  $Iterates in reverse order by default$
- B
  $Cannot be used with arrays — only ArrayList$
- C
  $Cannot modify the array element through the loop variable x$
  check_circle
- D
  $Allows modification by assigning to x$
Why
$<code> x </code> is a copy of arr[i]. Reassigning x has no effect on arr. To modify arr in place, use the indexed for loop.$
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