Calling a Void Method with Parameters Practice

Sample questions

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1. Sample 1difficulty 3/5

   public class Cell {
       public int v;
   }
   public class Helper {
       public static void bump(Cell c) {
           c.v++;
       }
   }
   // ...
   Cell c = new Cell();
   c.v = 10;
   Helper.bump(c);
   System.out.println(c.v);

   What is printed?

   • A

     11

     check_circle
   • B

     10

   • C

     0

   • D

     Compile-time error

   Why

   The reference is passed by value; bump modifies the same object's field through that reference.

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2. Sample 2difficulty 3/5

   public class Helper {
       public static void fill(int[] a) {
           a[0] = 99;
       }
   }
   // ...
   int[] arr = {1, 2, 3};
   Helper.fill(arr);
   System.out.println(arr[0]);

   What is printed?

   • A

     99

     check_circle
   • B

     1

   • C

     0

   • D

     Compile-time error

   Why

   Arrays are reference types; the method modifies the same array object, so arr[0] becomes 99.

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3. Sample 3difficulty 3/5

   public class Helper {
       public static void inc(int n) { n++; }
   }
   // ...
   int x = 5;
   Helper.inc(x);
   System.out.println(x);

   What is printed?

   • A

     5

     check_circle
   • B

     6

   • C

     0

   • D

     Compile-time error

   Why

   Java passes primitives by value; modifying the parameter n inside inc does not affect x.

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