Which expression yields <code2.5</code when <codeint a = 5;</code?

Answer: (double) a / 2 <code(double) a / 2</code casts first, then divides → 5.0 / 2 = 2.5. <code(double)(a/2)</code casts after the int division → 2.0.

Answer: 2.25 Casting a to double before division forces double division, so 9.0 / 4 = 2.25.

<codeint a = 7; double b = a / 2;</code — <codeb</code equals

Answer: 3.0 Right side first: int division a/2 = 3; assigned to double → 3.0.

AP Computer Science A · Topic 1.5

Casting and Ranges of Variables Practice

Q: Which expression yields <code2.5</code when <codeint a = 5;</code?

Answer: (double) a / 2 <code(double) a / 2</code casts first, then divides → 5.0 / 2 = 2.5. <code(double)(a/2)</code casts after the int division → 2.0.

Q: What is printed?

Answer: 2.25 Casting a to double before division forces double division, so 9.0 / 4 = 2.25.

Q: <codeint a = 7; double b = a / 2;</code — <codeb</code equals

Answer: 3.0 Right side first: int division a/2 = 3; assigned to double → 3.0.

Part of Primitive Types.

Practice questions

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Sample questions

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Sample 1difficulty 3/5
$Which expression yields <code> 2.5 </code> when <code> int a = 5; </code> ?$
- A
  $a / 2.0 / 2$
- B
  $(double) (a / 2)$
- C
  $a / 2$
- D
  $(double) a / 2$
  check_circle
Why
$<code> (double) a / 2 </code> casts first, then divides \to 5.0 / 2 = 2.5. <code> (double)(a/2) </code> casts after the int division \to 2.0.$
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Sample 2difficulty 3/5
```
int a = 9;
int b = 4;
double r = (double) a / b;
System.out.println(r);
```
$What is printed?$
- A
  $2$
- B
  $2.0$
- C
  $2.25$
  check_circle
- D
  $2.5$
Why
$Casting a to double before division forces double division, so 9.0 / 4 = 2.25.$
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Sample 3difficulty 3/5
$<code> int a = 7; double b = a / 2; </code> — <code> b </code> equals$
- A
  $3$
- B
  $3.0$
  check_circle
- C
  $Compile error$
- D
  $3.5$
Why
$Right side first: int division a/2 = 3; assigned to double \to 3.0.$
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Sample 4difficulty 3/5
$What is the value of <code> 7.0 / 2 </code> ?$
- A
  $3.5$
  check_circle
- B
  $3$
- C
  $Compiler error$
- D
  $4$
Why
$A <code> double </code> operand promotes the other to <code> double </code>; 7.0 / 2 = 3.5.$
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Sample 5difficulty 3/5
```
int a = 9;
int b = 4;
double r = (double)(a / b);
System.out.println(r);
```
$What is printed?$
- A
  $2.0$
  check_circle
- B
  $2.25$
- C
  $2$
- D
  $2.5$
Why
$The cast applies after the int division a / b which is 2; converting 2 to double gives 2.0.$
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