AP Chemistry · Topic 7.9

Introduction to Le Chatelier's Principle Practice

Part of Equilibrium.(TRA-8.A)

Practice questions

13

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Sample questions

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  1. Sample 1difficulty 1/5

    A sealed glass tube containing the equilibrium 2 NO2(g, brown) <-> N2O4(g, colorless), delta H = -57.2 kJ/mol (forward), is placed in three water baths in succession: ice water, room-temperature water, and hot water. Observations: ice bath - tube becomes nearly colorless; room temp - light brown; hot bath - dark brown.

    ice 0 C clear 25 C light brown 80 C dark brown 2 NO2 (brown) <-> N2O4 (clear)

    Which observation is most consistent with the forward reaction being exothermic?

    • A

      color is darker in cold water

    • B

      color is independent of temperature

    • C

      color darkens upon heating, indicating shift toward NO2 (reactant) when T rises

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    • D

      color lightens upon heating

    Why

    For an exothermic forward reaction, raising T shifts equilibrium toward reactants. Reactant NO2 is brown, so dark brown at high T is consistent.

  2. Sample 2difficulty 1/5

    A student adds the following stresses one at a time to separate samples of an equilibrium mixture of [Co(H2O)6]^2+ (pink) <-> [CoCl4]^2- (blue) + 6 H2O (delta H > 0 forward) and records color change: Trial A: heat the solution -> turns blue Trial B: add concentrated HCl -> turns blue Trial C: add AgNO3 -> turns pink Trial D: add water -> turns pink

    Trial A confirms that the forward reaction is:

    • A

      non-spontaneous at all temperatures

    • B

      at equilibrium with K = 1

    • C

      exothermic, since heating shifts toward reactants

    • D

      endothermic, since heating shifts the equilibrium toward products (blue)

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    Why

    For an endothermic forward reaction, increasing T shifts to the right (products). Solution turning blue indicates more [CoCl4]^2-.

  3. Sample 3difficulty 1/5

    A student adds the following stresses one at a time to separate samples of an equilibrium mixture of [Co(H2O)6]^2+ (pink) <-> [CoCl4]^2- (blue) + 6 H2O (delta H > 0 forward) and records color change: Trial A: heat the solution -> turns blue Trial B: add concentrated HCl -> turns blue Trial C: add AgNO3 -> turns pink Trial D: add water -> turns pink

    Stress Observation A: heat turns blue B: add HCl turns blue C: add AgNO3 turns pink D: add water turns pink

    Which observation is best explained by Le Chatelier's principle removing Cl-?

    • A

      Trial A

    • B

      Trial B

    • C

      Trial C

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    • D

      Trial D

    Why

    AgNO3 precipitates AgCl, removing Cl-. The equilibrium shifts back toward [Co(H2O)6]^2+ (pink).

  4. Sample 4difficulty 2/5

    The reaction 2 NO2(g) <-> N2O4(g) is at equilibrium when the container volume is suddenly decreased at the dashed line.

    2 NO2(g) <-> N2O4(g) time N2O4 NO2 decrease V

    The plot is consistent with which response to a volume decrease?

    • A

      Shift to the side with fewer moles of gas (toward N2O4)

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    • B

      Both species rise equally

    • C

      No shift, since K is constant

    • D

      Shift to the side with more moles of gas (toward NO2)

    Why

    Decreasing volume increases pressure; the system shifts toward fewer moles of gas. 2 mol NO2 -> 1 mol N2O4 reduces moles, so equilibrium shifts toward N2O4.

  5. Sample 5difficulty 2/5

    reaction coordinate solid: no catalyst dashed: catalyzed

    What does the catalyst change?

    • A

      Lowers Ea (forward and reverse) but not K

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    • B

      Increases K

    • C

      Changes dH

    • D

      Lowers Ea forward only and increases K

    Why

    A catalyst lowers activation energy for both forward and reverse paths equally; equilibrium is reached faster but K is unchanged.

AP Chemistry · 7.9 Introduction to Le Chatelier's Principle — Practice Questions | Acemy