The octet rule states that atoms tend to bond such that they have valence electrons.

Answer: 8 Most main-group atoms (Z ≤ 20) achieve 8 valence electrons (full s and p) for stability. Hydrogen and helium are duet (2).

The Lewis structure of H₂O has

Answer: 2 single O-H bonds and 2 lone pairs on O O has 6 valence electrons: 2 are shared with H atoms (2 single bonds = 4 e⁻), and 4 remain as 2 lone pairs.

In the N2 Lewis structure, the N-N bond order is:

Answer: 3 Three lines between the nitrogens indicate a triple bond, so the bond order is 3.

AP Chemistry · Topic 2.5

Lewis Diagrams Practice

Part of Compound Structure and Properties.(SAP-4.A)

Practice questions

Want a predicted score for the whole AP CHEM exam? Take the 20-question diagnostic and Lumi will plan the rest.

Take diagnosticarrow_forward Practice all 2.5

Sample questions

5 of 13 — sign in to practice the rest with adaptive difficulty and mastery tracking.

Sample 1difficulty 1/5
$The octet rule states that atoms tend to bond such that they have _______ valence electrons.$
- A
  $10$
- B
  $8$
  check_circle
- C
  $2$
- D
  $4$
Why
$Most main-group atoms (Z \leq 20) achieve 8 valence electrons (full s and p) for stability. Hydrogen and helium are duet (2).$
View full solution & statsarrow_forward
Sample 2difficulty 1/5
$The Lewis structure of H₂O has$
- A
  $A double bond and no lone pairs$
- B
  $1 bond and 3 lone pairs on O$
- C
  $An ionic structure$
- D
  $2 single O-H bonds and 2 lone pairs on O$
  check_circle
Why
$O has 6 valence electrons: 2 are shared with H atoms (2 single bonds = 4 e⁻), and 4 remain as 2 lone pairs.$
View full solution & statsarrow_forward
Sample 3difficulty 2/5
$In the N2 Lewis structure, the N-N bond order is:$
- A
  $3$
  check_circle
- B
  $1$
- C
  $1.5$
- D
  $2$
Why
$Three lines between the nitrogens indicate a triple bond, so the bond order is 3.$
View full solution & statsarrow_forward
Sample 4difficulty 2/5
$Carbon dioxide is a linear molecule formed by two C=O double bonds. The Lewis structure shows lone pairs on each oxygen.$
$The Lewis structure of CO2 contains how many sigma and pi bonds total?$
- A
  $2 sigma and 1 pi$
- B
  $2 sigma and 2 pi$
  check_circle
- C
  $1 sigma and 3 pi$
- D
  $4 sigma and 0 pi$
Why
$CO2 has two C=O double bonds. Each double bond is 1 sigma + 1 pi, giving 2 sigma + 2 pi.$
View full solution & statsarrow_forward
Sample 5difficulty 2/5
$In CO₂, each C-O bond is a$
- A
  $Coordinate covalent$
- B
  $Single bond$
- C
  $Triple bond$
- D
  $Double bond$
  check_circle
Why
$O=C=O. Two double bonds satisfy octets for both C and O.$
View full solution & statsarrow_forward

Predict my AP scorearrow_forward