AP Calculus AB · Topic 5.3

Determining Concavity Practice

Part of Analytical Applications of Differentiation.(FUN-4.C)

Practice questions

18

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Sample questions

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  1. Sample 1difficulty 2/5

    This concave-down (hill-shaped) graph has

    • A

      Cannot tell

    • B

      f=0f'' = 0

    • C

      f>0f'' > 0

    • D

      f<0f'' < 0

      check_circle

    Why

    Concave down ⇔ f<0f'' < 0.

  2. Sample 2difficulty 2/5

    This U-shaped graph is concave up, so

    • A

      f(x)=0f''(x) = 0

    • B

      f(x)<0f''(x) < 0

    • C

      f(x)>0f'(x) > 0

    • D

      f(x)>0f''(x) > 0

      check_circle

    Why

    Concave up ⇔ f>0f'' > 0.

  3. Sample 3difficulty 2/5

    For f(x)=x4f(x) = x^4, f(x)=12x20f''(x) = 12 x^2 \ge 0. So ff is

    • A

      Concave up everywhere

      check_circle
    • B

      Linear

    • C

      Has an inflection at x=0x = 0

    • D

      Concave down everywhere

    Why

    f0f'' \ge 0, with equality only at x=0x = 0 (no sign change), so concave up everywhere.

  4. Sample 4difficulty 2/5

    For ff with f(x)>0f''(x) > 0 on an interval, the graph is

    • A

      Linear

    • B

      Decreasing

    • C

      Concave down

    • D

      Concave up

      check_circle

    Why

    f>0f'' > 0ff' increasing ⇔ concave up.

  5. Sample 5difficulty 2/5

    For f(x)=x36x2+9xf(x) = x^3 - 6x^2 + 9x, on what interval is ff concave up?

    • A

      (,1)(-\infty, 1)

    • B

      (1,3)(1, 3)

    • C

      (,2)(-\infty, 2)

    • D

      (2,)(2, \infty)

      check_circle

    Why

    f(x)=6x12>0x>2f''(x) = 6x - 12 > 0 \Leftrightarrow x > 2.