AP Calculus AB · Topic 4.3

Rates of Change in Applied Contexts Practice

Part of Contextual Applications of Differentiation.(CHA-3.C)

Practice questions

4

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Sample questions

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  1. Sample 1difficulty 2/5

    If C(100)=5000C(100) = 5000 and C(100)=12C'(100) = 12, the cost of producing the 101st unit is approximately

    • A

      50125012

    • B

      1212

    • C

      50005000

    • D

      \5012butthemarginalcost( — but the marginal cost (12$) approximates the additional cost

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    Why

    Marginal cost C(100)=12C'(100) = 12 approximates the cost of unit 101.

  2. Sample 2difficulty 2/5

    If C(x)C(x) is total cost for xx items, "marginal cost" means

    • A

      C(x)C'(x)

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    • B

      C(x)dx\int C(x)\,dx

    • C

      C(x)C(x)

    • D

      C(x)/xC(x)/x

    Why

    Marginal cost = derivative of cost = C(x)C'(x) \approx cost of the next item.

  3. Sample 3difficulty 2/5

    If R(x)=x(1002x)R(x) = x(100 - 2x) is revenue from selling xx units, marginal revenue at x=20x = 20 is

    • A

      6060

    • B

      8080

    • C

      00

    • D

      2020

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    Why

    R(x)=100x2x2R(x) = 100x - 2x^2. R(x)=1004xR'(x) = 100 - 4x. At x=20x = 20: 2020.

  4. Sample 4difficulty 2/5

    If P(x)=R(x)C(x)P(x) = R(x) - C(x) is profit, profit is maximized when

    • A

      x=0x = 0

    • B

      R(x)=C(x)R'(x) = C'(x)

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    • C

      R(x)=C(x)R(x) = C(x)

    • D

      P(x)=0P(x) = 0

    Why

    P(x)=0R(x)=C(x)P'(x) = 0 \Rightarrow R'(x) = C'(x) — marginal revenue equals marginal cost.