AP Biology · Topic 8.6
Biodiversity Practice
Part of Ecology.(SYI-3.A)
Practice questions
6
Sample questions
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Sample 1difficulty 2/5
Three forest plots were surveyed. Plot 1 contained 5 species, Plot 2 contained 8, Plot 3 contained 12. Total individual counts were similar across plots.
Which plot has the greatest species richness?
- A
Plot 1 (5 species)
- B
All have equal richness.
- C
Plot 2 (8 species)
- Dcheck_circle
Plot 3 (12 species)
Why
Species richness is simply the count of distinct species in a sample. Plot 3 has the highest count (12).
- A
Sample 2difficulty 2/5
Major causes of biodiversity loss (the "evil quartet") include
- A
Excess rainfall, increased UV exposure, soil enrichment, atmospheric warming (and ozone)
- B
Genetic drift, balancing selection, gene flow, mutation accumulation (and inbreeding)
- Ccheck_circle
Habitat loss, invasive species, pollution, overharvesting (and climate change)
- D
Native predation, mutualism breakdown, parasite cycles, disease emergence (and exclusion)
Why
These anthropogenic drivers, plus climate change, account for most biodiversity decline.
- A
Sample 3difficulty 2/5
Species diversity has two components:
- A
Habitat richness (number of biomes) and habitat evenness (relative area)
- B
Genetic richness (allele variation) and genetic evenness (allele frequency)
- C
Trophic richness (number of levels) and trophic evenness (energy per level)
- Dcheck_circle
Species richness (number of species) and species evenness (relative abundance)
Why
Two communities can have the same richness but very different evenness; both contribute to overall diversity.
- A
Sample 4difficulty 3/5
The species-area curve shown predicts that doubling island area will:
- Acheck_circle
Increase species number, but less than double (S = cA^z, z<1)
- B
Reduce species number due to competition
- C
Triple the species number
- D
Double the species number exactly
Why
Empirical species-area relationships fit S = cA^z with z usually 0.2-0.35; species number rises with area but with diminishing returns.
- A
Sample 5difficulty 3/5
Two ponds were sampled. Pond X contained 50 of species A, 30 of B, 20 of C. Pond Y contained 90 of A, 5 of B, 5 of C. Both have 100 individuals total. Simpson's diversity index D = 1 - sum(pi^2).
Which pond has greater Simpson's diversity, and why?
- Acheck_circle
Pond X, because individuals are spread more evenly across species.
- B
Pond Y, because one species dominates.
- C
Pond Y, because of higher species richness.
- D
Both ponds have equal diversity.
Why
D(X) = 1 - (0.25 + 0.09 + 0.04) = 0.62. D(Y) = 1 - (0.81 + 0.0025 + 0.0025) = 0.185. Greater evenness in X yields higher Simpson's diversity.
- A