AP Biology · Topic 8.3

Population Ecology Practice

Part of Ecology.(SYI-2.B)

Practice questions

29

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Sample questions

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  1. Sample 1difficulty 2/5

    K

    The S-shaped logistic growth curve plateaus at the population's

    • A

      Carrying capacity (K)

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    • B

      Initial size (N0)

    • C

      Intrinsic growth rate (r)

    • D

      Per capita death rate (d)

    Why

    Logistic: dN/dt = rN(K-N)/K. As N approaches K, growth slows to zero.

  2. Sample 2difficulty 2/5

    A bacterial culture was sampled hourly for 8 hours after inoculation in fresh media. Cell density was plotted on a semi-log scale.

    Time (hr) log(N) lag log stationary

    What does the lag phase represent biologically?

    • A

      Cells are synthesizing enzymes and adjusting to the new medium before rapid division.

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    • B

      DNA replication is inhibited.

    • C

      The population has reached carrying capacity.

    • D

      Cells are dying due to nutrient deprivation.

    Why

    During lag, cells acclimate, synthesize ribosomes/enzymes, and prepare to divide. The population doesn't yet grow exponentially.

  3. Sample 3difficulty 2/5

    Males Females

    The age-structure pyramid shown best predicts what for the population?

    • A

      Stable or declining population

    • B

      Negative growth in 50 years

    • C

      Rapid future growth (expanding population)

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    • D

      Equal growth and death rates

    Why

    A broad base with each younger cohort larger than the next indicates a high reproductive potential and predicts rapid expansion.

  4. Sample 4difficulty 2/5

    K Time N

    At which population size does the logistic growth curve show the maximum dN/dt?

    • A

      N = K

    • B

      N just below K

    • C

      N = K/2

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    • D

      N = 0

    Why

    In the logistic model dN/dt = rN(1 - N/K), the maximum growth rate occurs at N = K/2, the inflection point of the S-curve.

  5. Sample 5difficulty 2/5

    Researchers captured 100 fish in a lake, marked them, and released them. One week later they captured 80 fish, of which 20 were marked.

    Variable Count Marked (M) 100 Recapture (C) 80 Marked-recap (R) 20

    Using N = (M x C)/R, what is the estimated population size?

    • A

      400 fish

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    • B

      1600 fish

    • C

      100 fish

    • D

      200 fish

    Why

    N = (100 x 80)/20 = 8000/20 = 400 fish.

AP Biology · 8.3 Population Ecology — Practice Questions | Acemy