AP Physics 1 · Topic 6.6

Motion of Orbiting Satellites Practice

Part of Energy and Momentum of Rotating Systems.(TOP-6.F)

Practice questions

8

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Sample questions

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  1. Sample 1difficulty 4/5

    r 2r

    How much energy must be added to move a satellite of mass mm from a circular orbit of radius rr to a circular orbit of radius 2r2r around a planet of mass MM?

    • A

      GMm4r-\dfrac{GMm}{4r}

    • B

      +GMmr+\dfrac{GMm}{r}

    • C

      +GMm4r+\dfrac{GMm}{4r}

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    • D

      +GMm2r+\dfrac{GMm}{2r}

    Why

    E2E1=GMm/(4r)(GMm/(2r))=GMm/(4r)E_2 - E_1 = -GMm/(4r) - (-GMm/(2r)) = GMm/(4r).

  2. Sample 2difficulty 4/5

    r

    A satellite of mass mm orbits at radius rr around a planet of mass MM. Its orbital kinetic energy is:

    • A

      2GMmr\dfrac{2GMm}{r}

    • B

      GMm2r-\dfrac{GMm}{2r}

    • C

      GMmr\dfrac{GMm}{r}

    • D

      GMm2r\dfrac{GMm}{2r}

      check_circle

    Why

    From mv2/r=GMm/r2mv^2/r = GMm/r^2, so K=12mv2=GMm/(2r)K = \tfrac12 mv^2 = GMm/(2r).

  3. Sample 3difficulty 4/5

    Planet X has twice the mass and half the radius of Earth. What is the ratio of escape velocity from X to escape velocity from Earth, vX/vEv_X/v_E?

    • A

      2\sqrt{2}

    • B

      22

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    • C

      44

    • D

      12\tfrac{1}{2}

    Why

    vesc=2GM/Rv_{esc} = \sqrt{2GM/R}. Ratio is (2M)/(R/2)/M/R=4=2\sqrt{(2M)/(R/2)} / \sqrt{M/R} = \sqrt{4} = 2.

  4. Sample 4difficulty 4/5

    r 9r

    A moon at orbital radius rr has period TT. A second moon orbits the same planet at radius 9r9r. What is its period in terms of TT?

    • A

      81T81T

    • B

      27T27T

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    • C

      3T3T

    • D

      9T9T

    Why

    Kepler's third law: T2r3T^2 \propto r^3. So T2/T=(9)3/2=27T_2/T = (9)^{3/2} = 27.

  5. Sample 5difficulty 4/5

    A satellite has period T=24T = 24 h around Earth at radius RgR_g. A second satellite has period T=3T = 3 h. What is its orbital radius?

    • A

      Rg/4R_g/4

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    • B

      Rg/3R_g/3

    • C

      Rg/8R_g/8

    • D

      Rg/2R_g/2

    Why

    T2r3T^2 \propto r^3. r2/Rg=(3/24)2/3=(1/8)2/3=1/4r_2/R_g = (3/24)^{2/3} = (1/8)^{2/3} = 1/4.